Jump to content
  • 0

pomoc Vypsat lidi co maji hodnotu


Zixik

Dotaz

Cafko mam problemek chci aby se vypsali lidi co maji treba v DB prommenou CHAT na 1 mam to takto ale nefunguje to (chci jmena ne ID)

 

$result = dbquery(
"SELECT user_name , user_chat  FROM  ".DB_USERS."");

$members = array();
while ($data = dbarray($result)) 
{
if($data['user_chat'] == 1)
{
	array_push($members, $data['user_name'], $data['user_chat']);
}
}
echo"

";echo " Online na chatu : ".count($members)."
\n";

 

 

user_chat

 

je ono

Link to comment
Share on other sites

1 odpověd na tuto otázku

Recommended Posts

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...